A Guide to Stoichiometry!
Meant to be helpful but most likely isn't! :D
CaO + CO2 --> Ca(CO3)
Let's start simple! Reaction type, balancing and state of matter!
Mass to Molars! I mean Mass to Mass!
- CaO- 40.0
- CO2- 12.011
- Ca(CO3)- 100.086
7 g CaO | 1 mol. CaO | 1 mol Ca(CO3) | 100.086 g Ca(CO3)
------------------------------------------------------------------------------------ = 17.4 g Ca(CO3)
(Blank) | 40.078 CaO | 1 mol CaO | 1 mol Ca(CO3)
Using the same procedure Mr. This video is too quiet uses, I found there would be 17.4 g. of Ca(CO3) if we had 7 grams of Calcium Oxide. We would also have 17.4 g. of Ca(CO3) if we started with 7 g. of CO2 because all of the coefficients in our equations are 1.
Moles to Moles Conversion
11.30 mol CaO | 1 mol Ca(CO3)
---------------------------------------------- =11.30 mol Ca(CO3)
(Leave blank) | 1 mol CaO
It'd be boring for me to tell you so how about a nice young lady explains it to you instead?
Using that same exact method is how we got 11.30 mol. of Ca(CO3) from 11.30 mol. of CaO